Mathematics
8 Online
OpenStudy (anonymous):
Help! I've been trying to do this for the pas hour or so. I've been using the Pythagorean theorem and I can't even get close to any of the options
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
the 2nd one? or the 1st one
OpenStudy (anonymous):
both? i want to learn how to do it
OpenStudy (anonymous):
ok let's see....
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OpenStudy (anonymous):
the first one is wrong btw
OpenStudy (anonymous):
as u can see, the pathogrem threom is
\(a^2+b^2=c^2\)
OpenStudy (anonymous):
oh yeah i randomly clicked that tbh i was getting frustrated
OpenStudy (anonymous):
whereas a and b is the height and the radius and c is the slant height
OpenStudy (anonymous):
so the first one... you plug the numbers in
\(9^2+4^2=c^2\)
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OpenStudy (anonymous):
i did 8^2+9^2 and got 145
and then i divided that in half so i got 72.5
OpenStudy (anonymous):
u will find it not a perfect square tho
OpenStudy (anonymous):
oh wait its 4 oh its half of the diameter ohhhhhhhhhhh
OpenStudy (anonymous):
yeah...
OpenStudy (anonymous):
okay thank you so much ahh i'll try it now and see if i can get it
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OpenStudy (anonymous):
ok.
OpenStudy (acxbox22):
not really
OpenStudy (anonymous):
yeah i know ^u^ i was about to edit that in
OpenStudy (anonymous):
lol
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OpenStudy (acxbox22):
asking a good question does not involve attention grabbers
OpenStudy (anonymous):
:/ ok
OpenStudy (anonymous):
\(\tiny{I~suppose~so...}\)
OpenStudy (anonymous):
so I got 9.85, is that right?
OpenStudy (anonymous):
um hum
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OpenStudy (anonymous):
or 9.8 bc im supposed to round it
OpenStudy (anonymous):
yesh
OpenStudy (anonymous):
now try the second one :P u can do this
OpenStudy (anonymous):
22.8?
OpenStudy (anonymous):
thats too high...
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OpenStudy (anonymous):
um hum... remember.. the diameter...
OpenStudy (anonymous):
ohh right
so 11.4
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
god ur amazing thank you :0
OpenStudy (anonymous):
ary i was trying to solve it using mental math
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OpenStudy (anonymous):
its cool ^U^ mental math is hard when you have exponentss
OpenStudy (anonymous):
yeah but u don't really need to like solve solve it i know so it's cool ^o^
OpenStudy (anonymous):
any more?
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
since when r u here sai?
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OpenStudy (anonymous):
just now.. u have a problem?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
good
OpenStudy (anonymous):
XD jk im not that mean
OpenStudy (anonymous):
:P
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OpenStudy (anonymous):
ah i think i have another one for u let me screenshot it
OpenStudy (anonymous):
oh sh*t i hate those problems but ok i'll try to help u
OpenStudy (anonymous):
it would be a lot easier if it were cubes man
OpenStudy (anonymous):
yeah same lmao
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OpenStudy (anonymous):
i know i did something wrong bc i got 8.06
OpenStudy (anonymous):
find the diagonal of the base first
OpenStudy (anonymous):
tell me u know how to do that...
OpenStudy (anonymous):
lol ik how to do that!!!!!!!! b ut of course... im too lazy :P molly.. I BELIEVE IN U!
OpenStudy (anonymous):
so u like multiply the length of one side by the square root of 2 right
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OpenStudy (anonymous):
i don't get u wht did u get as the answer tho?
OpenStudy (anonymous):
im lost tbh
OpenStudy (anonymous):
here hang on i think they gave us instructions
OpenStudy (anonymous):
... let's see...
\(4^2+10^2=c^2\) solve this
OpenStudy (anonymous):
*sai askes: where did you get that from?*
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OpenStudy (anonymous):
58?
OpenStudy (anonymous):
116=\(x^2\)
OpenStudy (anonymous):
116 / 2 = 58 = x
right
OpenStudy (anonymous):
no...
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OpenStudy (anonymous):
the square root! not divided by 2!
OpenStudy (anonymous):
no u square root it not divide it by 2
OpenStudy (anonymous):
its \(\sqrt116\)
OpenStudy (anonymous):
sorry lmao my brain is being dumb i knew i was doing that wrong
OpenStudy (anonymous):
\(\sqrt{116}\)
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OpenStudy (anonymous):
not 116 \(\div\) 2!!
OpenStudy (anonymous):
10.7
OpenStudy (anonymous):
jeez he got it
OpenStudy (anonymous):
so its about... 11
OpenStudy (anonymous):
round it!! don't make it harder!! make it easier so its 11
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OpenStudy (anonymous):
ty u guys
OpenStudy (anonymous):
now solve this
\(11^2+10^2=c^2\)
OpenStudy (anonymous):
well its multiple choice and im supposed to round it to the nearest tenth so 10.77 would be 10.8 there isnt even an option for 11
OpenStudy (anonymous):
221=\(c^2\)
OpenStudy (anonymous):
no it's not done yet... u found the diagonal of the BASE not the RECTANGULAR PRISM
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OpenStudy (anonymous):
14.86
oh okay
OpenStudy (anonymous):
:Dnex t question
OpenStudy (anonymous):
=-= 15!
OpenStudy (anonymous):
the answer is 14.7 tho
OpenStudy (anonymous):
:P
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OpenStudy (anonymous):
u gtta ROUNDD welll..... true... but then.... D: I WANNA ROUND IT
OpenStudy (anonymous):
now for the enxt problem...
solve this:
\(14^2+3^2=c^2\)
OpenStudy (anonymous):
205=\(c^2\)
OpenStudy (anonymous):
somewhere around 14. so now solve this:
\(14^2+4^2=c^2\)
OpenStudy (anonymous):
and then u can get ur answer
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OpenStudy (anonymous):
14.31?
OpenStudy (anonymous):
i think it should be a bit more than that
OpenStudy (anonymous):
through mental math, i figured that it should be 14.8
OpenStudy (anonymous):
hat was it last time this answer is like 14.5
OpenStudy (anonymous):
14.56 so 14.7
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OpenStudy (anonymous):
somethinglike that
OpenStudy (anonymous):
so 14.8? yeah immga go withh tha
OpenStudy (anonymous):
ugh lag