Question

How should I simplify this trig problem?

Answer 1

\[\frac{ \csc^2x-\cot^2x }{ \sin(-x)cotx }\]

Answer 2

@mathmath333 @jim_thompson5910

Answer 3

start with \(1+cot^2x=csc^2x\)

Answer 4

also sin(-x)=-sin(x)

Answer 5

so \[\frac{ 1 }{ -\sin(x)cotx }\]

Answer 6

yea
and 1/cot(x)=?

Answer 7

well i can put as cos/sin

Answer 8

that works \(\dfrac{1}{-\sin(x)*\dfrac{\cos x}{\sin x}}\)

Answer 9

so i get -sinx(cosx)/sinx, the sins cross out and i'm left with 1/-cosx?

Answer 10

with is also -sec?

Answer 11

yea

Answer 12

thank you :)

Answer 13

np