Question

Prove that (trig)

Answer 1

\[\frac{ -\sin^2x }{ \tan^2x }=\cos^2x\]

Answer 2

For some reason i keep getting -cos^2x..

Answer 3

unless -sin^2x=sin^2x

Answer 4

no it does not

Answer 5

then not sure what i did wrong

Answer 6

the identity is \(\bf false\)

Answer 7

nothing

Answer 8

the problem is wrong
take a look
the left hand side is negative for all x

Answer 9

\[-\cos^2x\ne \cos^2x\]

Answer 10

\[-1\ne1\]

Answer 11

so just a false identity? it asks me to verify so i thought it must be true

Answer 12

probably a typo

Answer 13

don't think any more about it, it is waste of time
it is not true
done

Answer 14

thanks