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Solve the system of equations using the substitution method. 1. y=x^2+2x-1 y=-2x-4 2. y=2x^2-5 y=11-4x
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for the first problem. you are given (in the second equation) that \(\large\color{black}{ \displaystyle y }\) is same thing as \(\large\color{black}{ \displaystyle -2x-4 }\) So, all you need to do is to substitute this (the -2x-4 ) instead of y into the first equation.
oh ok thank you that makes more sense
the substitution will occur the following way: YOUR FIRST EQUATION \(\large\color{black}{ \displaystyle \color{red}{y}=x^2+2x-1 }\) SUBSTITUTION \(\large\color{black}{ \displaystyle \color{red}{-2x-4}=x^2+2x-1 }\)
(I am lagging, excuse me)
simplify and factor.
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