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Mathematics 16 Online
OpenStudy (ivancsc1996):

Hi, can somebody help me prove this \(\forall n \in \mathbb{N}: gcd(f_{n+1},f_{n})=1\), where \(\{ f_{n} \} _{n=0}^\infty\) is the fibonacci sequence?

OpenStudy (ivancsc1996):

gcd is greatest common divisor

OpenStudy (anonymous):

Have you considered a proof by induction?

OpenStudy (anonymous):

Doing so shouldn't be too difficult. Use the fact that for two natural numbers \(a,b\), you have \(\gcd(a,b)=\gcd(a+b,b).\)

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