Question

Aright triangle has its right angle at (5,7) and the equation of one of its legs is 2x-y-3=0. Find the equation of the other leg.

Answer 1

help me here @iGreen

Answer 2

jamaica... i got (3/2, -3)

Answer 3

your other question was easier
i suggest you finish it first it will help you

Answer 4

i cant do it, please guide me, whats the next step :D

Answer 5

im only 12 years old, i need to solve this stuff to accelerate to senior high

Answer 6

on the first x=0 y becomes =13/7 for one point
if y=o x becomes =13/3
plot these points
draw the line get the slope
the question wants you to find the line at right angles thr0 the point (2,1)

Answer 7

13/7 how did you get this?

Answer 8

2x-y-3 =0
2(0) - y=3
y= -3/2

Answer 9

the slope of the line is (-3/7)
so one at right angles =(7/3) this is the locus or radius line

Answer 10

put x=o in the equation you are only left with y=

Answer 11

2x-y-3 =0
2(0) - y=3
y= -3/2

is this?

Answer 12

we are working on different equations i am on the first 3x+7y-13=0

Answer 13

the locus problem?

Answer 14

yes

Answer 15

ok, lets solve that first

Answer 16

i said this was easier and would help with the other

Answer 17

how did you get (3 , -7) as the slope?

Answer 18

did you plot the points ?

Answer 19

yup

Answer 20

well can you get the slope?

Answer 21

i mean 3/-7

Answer 22

using the slope formula?

Answer 23

yes

Answer 24

\[m = \frac{ 13/7 - 1 }{ 13/3 - 2 }\]

Answer 25

this?

Answer 26

your equation 3x+7y-13=0
so 7y =-3x =13
y =3/7(x)-13
so m=-(3/7)

Answer 27

yup

Answer 28

so i will use y-y1 = m(x-x1)?

Answer 29

the slope you need is at right angles thro (2,1) because that will be the radius line that you use to touch the point (2,1) it could any radius but it will be on this line

Answer 30

the intersection is point (2,1)

Answer 31

must go think on it