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Mathematics 10 Online
OpenStudy (anonymous):

i need help i am confused can someone help me fan and medal if possible

OpenStudy (anonymous):

A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle.

OpenStudy (anonymous):

@djspeed @KaylaIsBae

OpenStudy (anonymous):

. 2 to the 3 over 5 power inches squared 2 to the 4 over 5 power inches squared 2 inches squared 2 to the 2 over 5 power inches squared

OpenStudy (anonymous):

@Demonx341

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

5th root is ambiguous to me. do you mean:\[\sqrt[5]{16}\]

OpenStudy (amistre64):

great now my latex coding is not working again ...

OpenStudy (amistre64):

|dw:1427209289145:dw|

OpenStudy (anonymous):

3.2

OpenStudy (anonymous):

and yes 5,16

OpenStudy (anonymous):

@amistre64

OpenStudy (amistre64):

recall how to find the area of a rectangle, what is the process we do?

OpenStudy (anonymous):

A=WL ?? @amistre64

OpenStudy (amistre64):

correct, so we are given W and L so we simply have to multiply them right |dw:1427209943587:dw|

OpenStudy (amistre64):

if we can determine like bases, then we can simply add the exponents ....

OpenStudy (amistre64):

can 16 be rewritten as a base 2 value?

OpenStudy (anonymous):

no

OpenStudy (amistre64):

really? 16 = 4*4 = 2*2*2*2 ....

OpenStudy (anonymous):

oh yes im sorry

OpenStudy (amistre64):

so lets use that :) |dw:1427210102371:dw|

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