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OpenStudy (anonymous):
i need help i am confused can someone help me fan and medal if possible
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OpenStudy (anonymous):
A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle.
OpenStudy (anonymous):
@djspeed @KaylaIsBae
OpenStudy (anonymous):
.
2 to the 3 over 5 power inches squared
2 to the 4 over 5 power inches squared
2 inches squared
2 to the 2 over 5 power inches squared
OpenStudy (anonymous):
@Demonx341
OpenStudy (anonymous):
@amistre64
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OpenStudy (amistre64):
5th root is ambiguous to me. do you mean:\[\sqrt[5]{16}\]
OpenStudy (amistre64):
great now my latex coding is not working again ...
OpenStudy (amistre64):
|dw:1427209289145:dw|
OpenStudy (anonymous):
3.2
OpenStudy (anonymous):
and yes 5,16
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OpenStudy (anonymous):
@amistre64
OpenStudy (amistre64):
recall how to find the area of a rectangle, what is the process we do?
OpenStudy (anonymous):
A=WL ?? @amistre64
OpenStudy (amistre64):
correct, so we are given W and L so we simply have to multiply them right
|dw:1427209943587:dw|
OpenStudy (amistre64):
if we can determine like bases, then we can simply add the exponents ....
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OpenStudy (amistre64):
can 16 be rewritten as a base 2 value?
OpenStudy (anonymous):
no
OpenStudy (amistre64):
really? 16 = 4*4 = 2*2*2*2 ....
OpenStudy (anonymous):
oh yes im sorry
OpenStudy (amistre64):
so lets use that :)
|dw:1427210102371:dw|
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