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Mathematics
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OpenStudy (anonymous):
please help i think it will be easy for a lot of people. will medal and fan for straight answers.
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OpenStudy (anonymous):
Go
OpenStudy (anonymous):
What is the value of the first quartile (Q1) of the data set?
OpenStudy (anonymous):
Firat find the median of your numbers
OpenStudy (anonymous):
61?
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OpenStudy (anonymous):
ok, now take only the numbers less than the median, and find the median out of those
OpenStudy (anonymous):
like add them? or what?
OpenStudy (anonymous):
no, just take away the number bigger than the median. so now you only look at 45, 51,52,and 58 and find the median
OpenStudy (anonymous):
52
OpenStudy (anonymous):
it's actually 51.5
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OpenStudy (anonymous):
oh ok i was counting 61 thats why
OpenStudy (anonymous):
you don't include 61 in this set. So you end up with 51 and 52 for the median, so you go in the middle,
OpenStudy (anonymous):
there you go!
OpenStudy (anonymous):
thanks so much!!!!
OpenStudy (amistre64):
to double chk
9 data points, divided by 4 is: 1Q = 2.something so we round up to 3 and pick the 3rd value
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OpenStudy (amistre64):
if we had ended up with say 1Q = 2, then we would have had to average the 2nd and 3rd values.
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