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Linear Algebra 13 Online
OpenStudy (anonymous):

I need help!! this is the last question on my test and im stuck Graph a line at home using the slope intercept form of the line with a slope of 3/2 and a y-intercept of -2. Once you have graphed your line. Answer the following in the text box: 1. Give the ordered pair (x, y) for the point that is at the y- intercept on your graph. 2.Give the ordered pair (x, y) for the second point that you plotted on your graph based on the slope of 3/2. 3.Tell whether your line has a positive slope of a negative slope.

OpenStudy (anonymous):

I will fan and give medal to whoever can help by 11:00 AM !!! Need help ASAP

OpenStudy (anonymous):

@OwlCoffe

OpenStudy (anonymous):

@OwlCoffee

OpenStudy (anonymous):

are you there?

OpenStudy (owlcoffee):

yes, I was giving the question soe thought.

OpenStudy (anonymous):

oh okay

OpenStudy (owlcoffee):

okay, you can determine the equation of any line with the form: \[y=mx+c\] "m" represents the slope, and "c"the y-interception. So the line would be: \[y=\frac{ 3x }{ 2 }-2\]

OpenStudy (anonymous):

I See..

OpenStudy (anonymous):

are you in england?

OpenStudy (owlcoffee):

Okay since we deduced the equation, we have to find the point that is the y-interception. Sinse I said, previously that the y-interception is given by the number without an "x" on it, I can tell that the y intercept is -2. Now, since any y- interception means x=0, I deduce that the point of the y-interception is (0,.2)

OpenStudy (owlcoffee):

(0,-2)* I liv in sweden by the way.

OpenStudy (anonymous):

thats sweet i live in the u.s

OpenStudy (owlcoffee):

okay, and tey the second part of the excercise

OpenStudy (anonymous):

You mean take?

OpenStudy (owlcoffee):

the* I'm writing in darkness haha

OpenStudy (owlcoffee):

and try*

OpenStudy (anonymous):

Oh okay

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