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Let u = <-5, -9>, v = <6, 8>. Find -8u - 2v. <52, 88> <-8, 2> <112, -28> <28, 56>
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did you try doing what I suggested.
-8<-5,-9>=? -2<6,8>=?
just apply the rules I showed
okay, thanks
a is a constant so au=<-5a,-9a> so if a=2 then 2u=<-10,-18>
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I got <112, -28>
\[-8<-5,-9>=<40,72> \\ -2<6,8>=<-12,-16>\] so you added 40 and -12 and then you added 72 and -16 and got 112 and -28 respectively ?
Oh, no. I added the 40 and 72, and the -12 and -16.... So I needed to add the 40 and -12 which is 28, and the 72 and -16 which is 56.
that sounds much better
<a,b>+<c,d>=<a+c,b+d> is the rule for adding vectors
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Okay, that's where I was confused.
Thank you!
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