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Mathematics 13 Online
OpenStudy (wade123):

@Loser66 @satellite73 @amistre64

OpenStudy (anonymous):

it has a critical point where the derivative is zero where is that?

OpenStudy (wade123):

at x?

OpenStudy (anonymous):

at what NUMBER is the derivative zero? i.e. for which x value ?

OpenStudy (wade123):

0

OpenStudy (anonymous):

ok and before that (for x values less than zero) is the derivative positive or negative?

OpenStudy (wade123):

negative!

OpenStudy (anonymous):

???

OpenStudy (wade123):

sorry it is lagging a bit

OpenStudy (anonymous):

when \(x=-8\) you are told \(f'(x)=5\) right?

OpenStudy (wade123):

yess

OpenStudy (anonymous):

is 5 positive or negative?

OpenStudy (asad786):

hey

OpenStudy (wade123):

positive! @satellite73

OpenStudy (wade123):

so it would be B coreect? @satellite73

OpenStudy (asad786):

what are we talking about exactly

OpenStudy (anonymous):

the derivative is positive to the left of zero is the function going up or down?

OpenStudy (wade123):

up

OpenStudy (wade123):

@satellite73 PLEASE HELP ME!

OpenStudy (wade123):

@misty1212 could you please help me?!

OpenStudy (misty1212):

HI!!

OpenStudy (wade123):

:)

OpenStudy (misty1212):

for negative x values (numbers to the left of zero) the derivative is positive that means the function is increasing for positive x values the derivative is negative, that means the function is decreasing

OpenStudy (misty1212):

at x = 0 the derivative is 0, that makes it a critical point, where the tangent line is horizontal

OpenStudy (misty1212):

|dw:1427251083943:dw|

OpenStudy (misty1212):

that means at \(x=0\) the function has a relative maximum as per the picture

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