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OpenStudy (anonymous):
it has a critical point where the derivative is zero
where is that?
OpenStudy (wade123):
at x?
OpenStudy (anonymous):
at what NUMBER is the derivative zero?
i.e. for which x value ?
OpenStudy (wade123):
0
OpenStudy (anonymous):
ok
and before that (for x values less than zero) is the derivative positive or negative?
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OpenStudy (wade123):
negative!
OpenStudy (anonymous):
???
OpenStudy (wade123):
sorry it is lagging a bit
OpenStudy (anonymous):
when \(x=-8\) you are told \(f'(x)=5\) right?
OpenStudy (wade123):
yess
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OpenStudy (anonymous):
is 5 positive or negative?
OpenStudy (asad786):
hey
OpenStudy (wade123):
positive! @satellite73
OpenStudy (wade123):
so it would be B coreect? @satellite73
OpenStudy (asad786):
what are we talking about exactly
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OpenStudy (anonymous):
the derivative is positive to the left of zero
is the function going up or down?
OpenStudy (wade123):
up
OpenStudy (wade123):
@satellite73 PLEASE HELP ME!
OpenStudy (wade123):
@misty1212 could you please help me?!
OpenStudy (misty1212):
HI!!
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OpenStudy (wade123):
:)
OpenStudy (misty1212):
for negative x values (numbers to the left of zero) the derivative is positive
that means the function is increasing
for positive x values the derivative is negative,
that means the function is decreasing
OpenStudy (misty1212):
at x = 0 the derivative is 0, that makes it a critical point, where the tangent line is horizontal
OpenStudy (misty1212):
|dw:1427251083943:dw|
OpenStudy (misty1212):
that means at \(x=0\) the function has a relative maximum as per the picture