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how to solve this by factoring 2x^2 - 3x = 0
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Take an x out of each term . So we have x(SOMETHING - SOMETHING) = 0
so is it two separate equations like x(x - 1) = 0 x-2 = 0?
No it's still one equation.
oh so x( 2 - 3)? I'm still kind of confused
If it's x( 2 - 3) , then we have 2x-3x.
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We want \[2x ^{2}\] instead.
$$ \Large { 2x^2 - 3x = 0 \\ \iff \\ x (2x-3) = 0 \\ \iff \\ x = 0 ~~or ~~ 2x-3 = 0 } $$
Oh ok I get it now :) thanks
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