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assume no denomiator equals 0. simplify 15p^3q^2/ 18p^2q 3a^2b/9ab^2
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first find the GCF of 15 and 18 can you do that?
yeah its 3
so divide 15 and 18 by 3 to simplify the numerals
now take the terms in p p^3 / p^2 = ?
5p^3 / 6p^2 like that?
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5 and 6 is right but you need to work out p^3 / p^2 when you divide you subtract the esponents for example x^4 / x^2 = x(4-2) = x^2
p^3 / p^2 = p^(3-2) = ?
so p^1
yes or just write p The 1 is understood now q^2 / q = ?
q^2 / q^1 =
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so q
= q^(2-1) = q
so we get 5pq --- 6
the second one is done in same way
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