Question

What are the solutions of 3x^2 + 15 = -6x?

Answer 1

when we have:
\[3x^2 +15=-6x\]
We can transport it to the form:
\[Ax^2 + Bx+C=0\]
All we do is adding 6x to both sides:
\[3x^2+6x+15=0\]
we can divide the whole equality by 3 to get:
\[x^2 + 2x +5=0\]
adn now, we have to use the quadratic formula to find the solutions:
\[x=\frac{ -2 \pm \sqrt{2^2 -4(1)(5)} }{ 2 }\]

Answer 2

-1 ± i
-1 ± 2i
-2 ± i
-2 ± 2i

Answer 3

does are the answer choices

Answer 4

okay, try operating the equality on my last posr. so you can find the value of x

Answer 5

i dont know how to set this kinda problem up in all honesty i was just looking for the answer

Answer 6

thing is, I am here to help you out, not to give you the answer, but I'll take another step for you:
\[x=\frac{ -2\sqrt{2^2-4(1)(5)} }{ 2 }\]

\[x=1 \pm \frac{ \sqrt{-16} }{ 2 }\]
\[x= 1 \pm 2i\]

Answer 7

sorry, it's:
\[x=-1 \pm 2i\]

Answer 8

well in this case i only needed the answer its the last problem of my test it wouldn't hurt to get one free answer when i have solved every last one of them but the problem i asked you but thanks anyway

Answer 9

no problem.