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Mathematics 18 Online
OpenStudy (gabylovesyou):

@iambatman How do i factor 5c^3(c^2 + 12c + 36)

OpenStudy (anonymous):

add like terms :)

OpenStudy (anonymous):

You can use sum of squares

OpenStudy (anonymous):

jk Simplifying 5c3(c2 + 12c + 36) Reorder the terms: 5c3(36 + 12c + c2) (36 * 5c3 + 12c * 5c3 + c2 * 5c3) (180c3 + 60c4 + 5c5) Factor out the Greatest Common Factor (GCF), '5c3'. 5c3(36 + 12c + c2) Factor a trinomial. 5c3((6 + c)(6 + c)) Final result: 5c3(6 + c)(6 + c) im not 100% if im correct

OpenStudy (anonymous):

\[(a+b)^2 \implies a^2+2ab+b^2\]

OpenStudy (anonymous):

So your a = c b = 6 :)

OpenStudy (gabylovesyou):

so answer is 5c^3(c + 6)^2

OpenStudy (anonymous):

Yeah, that looks good :), or you can write it as algebrahelper did

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