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Hi ( :can anyone help me solve this? Use interval notation to state the range of the quadratic function. f(x) = -2(x + 1)^2 - 3
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lets take it step by step
the smallest \((x+1)^2\) can be is 0, because if you square any non zero number it is positive
therefore the LARGEST \(-2(x+1)^2\) can be is zero, otherwise it is negative (less than zero)
and finally that means the largest \[-2(x+1)^2-3\] can be is \(-3\)
that makes the range all numbers less than or equal to \(-3\) which, in interval notation, is \[(-\infty, -3]\)
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\[(-\infty, -3]\]
Thank you
yw
would please help me with another question?
On which interval is f(x) = (x - 6)2 + 3 decreasing?
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