Question

Determine the type and number of solutions of 4x^2-3x+1=0

a. two real solutions <----- my answer
b. one real solution
c. two imaginary solutions

Answer 1

what did you get when you factored

Answer 2

\[D > 0\] - two real and unequal solutions
\[D = 0 \] real and equal solutions

Answer 3

\[D < 0 \] - no real roots

Answer 4

so its b

Answer 5

nah....according to ur question D = -7
D is negative

Answer 6

ok so its a?

Answer 7

when \[D < 0\] then no real roots.....
it means two imaginary solutions/roots

Answer 8

oh ok thanks

Answer 9

can you help me with another one

Answer 10

okay....

Answer 11

x^2+10x-25=0

Answer 12

wht u wanna find??

Answer 13

would this one be two solutions

Answer 14

find D.....

Answer 15

d=0

Answer 16

is that right?

Answer 17

D = b^2 - 4ac
= 100 - 4(-25) (1)
= 100 + 100
= 200

Answer 18

ok pretty confusing

Answer 19

as \[D > 0 \] it means 2 real and unequal solutions

Answer 20

so itts two solutions

Answer 21

@rishavraj

Answer 22

two real solutions...:)