Question

Determine the type and number of solutions of 4x^2-5x+1=0

a. two real solutions
b. one solution
c. tow imaginary solutions

Answer 1

find the discriminant please

Answer 2

how do i do that? sorry

Answer 3

the discriminant for any
ax^2+bx+c=0

is
b^2 - (4)*(a)*(c)

Answer 4

if you compare them:

4x^2-5x+1
ax^2+bx+c

what will your a b c be?

Answer 5

a=4 b=5 c=1?

Answer 6

close, b=-5

Answer 7

but that wouldn't matter, because you are squaring it anyway

Answer 8

ok, so
(-5)^2 - (4)*(4)*(1) = ?

Answer 9

9

Answer 10

yes, 9 is correct.

Answer 11

When the discriminant of the quadratic equation comes out to be a positive integer that means that the quadratic equation has 2 [real] integer solutions.

Answer 12

ok sot the answer is a?

Answer 13

yes

Answer 14

thanks for the help and your time :)

Answer 15

you welcme