This question has me completely lost.

The sum of the digits of a two-digit number is 12. The number formed by interchanging the digits is 54 more than the original number. What is the original number?

39
48
57

Question

This question has me completely lost.

The sum of the digits of a two-digit number is 12. The number formed by interchanging the digits is 54 more than the original number. What is the original number? 


39
48
57

anonymous · Answer

t + u = 12 
10u + t = 54 + 10t + u 
9u - 9t = 54 
u - t = 6 

u + t = 12 
t = 12 - u 

u - t = 6 
u - (12 - u) = 6 
u - 12 + u = 6 
2u = 6 + 12 
2u = 18 
u = 9 

9 + t = 12 
t = 12 - 9 
t = 3

anonymous · Answer

original: 39 
reversal: 93 

The number formed by interchanging the digits is 54 more than the original number 
39 + 54 = 93

thedj4jc · Answer

Thank you!!!!

anonymous · Answer

your welcome! did you understand how i got the answer?

thedj4jc · Answer

Kinda