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HELP PLEASE ! Solve: 3(x + 4) greater than or equal to x - 2
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3(x+4)=what using distributive property
3x + 12
so you have \[3x+12 \ge x-2 \]
yup
get your x's together and your non x terms on the opposing side by adding and subtracting on both sides
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2x > -14
4x is bigger or equal to -14
It's 2x , 3x - x
\[3x+12 \ge x-2 \\ \text{ subtract } x \text{ on both sides } \\ 3x-x+12 \ge x-x-2 \\ 2x+12 \ge -2 \] now try again to subtract your 12 on both sides and you have \[2x \ge -14\]
yup
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now the last step is to isolate the x factor on the left hand side
so it's x is bigger or equal to -7
yeah
good job
thanks
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np :)
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