Ask your own question, for FREE!
Mathematics 28 Online
OpenStudy (anonymous):

Which inequality matches the graph? -2x + 3y > 7 2x - 3y < 7 -3x + 2y ≥ 7 3x - 2y ≤ 7

OpenStudy (anonymous):

OpenStudy (anonymous):

@Nnesha Can you please help me :( I've been trying for 30 minutes +..

Nnesha (nnesha):

hmm sorry about that :( okay do you know how to solve inequality for y ?

OpenStudy (anonymous):

I know to take out the > & < because it's a solid line.

Nnesha (nnesha):

waoo nice yes right so you can cancel out A and B

Nnesha (nnesha):

last one is it 73 or 7 ?

OpenStudy (anonymous):

3x was a mistake

OpenStudy (anonymous):

i think it's c... @Nnesha

Nnesha (nnesha):

ohh okay so solve last two equation for y

Nnesha (nnesha):

how ?

OpenStudy (anonymous):

last two choices are : -3x + 2y ≥ 7 3x - 2y ≤ 7

Nnesha (nnesha):

okay so why do you think its C ?

OpenStudy (anonymous):

I read it wrong, I solved the equation now is it D? @Nnesha

Nnesha (nnesha):

okay but my question is same how is it D ??

OpenStudy (anonymous):

because it has a 3 on the number line?

Nnesha (nnesha):

okay but both equation have 3 to graph the equation you have to solve for y and remember when you divide or multiply both side by negative you must flip the inequality sign

Nnesha (nnesha):

same like slope intercept form but that equations have inequality sign instead of =" equal sign slope intercept form equation y = mx +b b is y-intercept which cross the y-axiss on the graph

OpenStudy (anonymous):

so the sign is going to be < with a line under it? @Nnesha

Nnesha (nnesha):

\[ \huge\rm -3x + 2y ≥7\] solve this for y first step to add 3x both side and then divide by 2

OpenStudy (anonymous):

so -3 would cancel out then 2y + 3x = 5 > 7? @Nnesha

Nnesha (nnesha):

|dw:1427407078497:dw| left side 3x can cancel out now divide both side by 2

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!