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OpenStudy (darkbluechocobo):

Help with Law of sines

OpenStudy (darkbluechocobo):

The information in the following problem allows you to construct 2 triangles, find C1 and C2 . A = 30°, a = 1.5 m, b = 2 m

OpenStudy (darkbluechocobo):

I am confused on how to draw this into two triangles.

OpenStudy (igreen):

'a' and 'b' are two legs of the triangle..the opposite and the adjacent.

OpenStudy (igreen):

Use Tangent.

OpenStudy (igreen):

Wait..just what exactly is your question?

OpenStudy (jhannybean):

law of sines states: \[\frac{sin~ A}{a} = \frac{sin~B}{b}=\frac{sin~C}{c}\]

OpenStudy (jhannybean):

So just match up the angle with the given side while using this ratio to find the unknown side or angle.

OpenStudy (darkbluechocobo):

Sorry I got disconnected :C

OpenStudy (darkbluechocobo):

Well The construction is what I dont understand. Like there are two answers, I don't know how to get the second

OpenStudy (darkbluechocobo):

|dw:1427479476513:dw|

OpenStudy (darkbluechocobo):

Then you would do a/sinA=b/sinB to get angle B

OpenStudy (darkbluechocobo):

\[\frac{ 1.5 }{ \sin30 }=\frac{ 2 }{ sinB }\]

OpenStudy (darkbluechocobo):

\[\frac{ 2\sin30 }{ 1.5 }\]

OpenStudy (darkbluechocobo):

\[B=\sin ^{-1}\frac{ 2\sin30 }{ 1.5 }\]

OpenStudy (darkbluechocobo):

B=41.8 degrees

OpenStudy (darkbluechocobo):

180-41.8-30=

OpenStudy (darkbluechocobo):

C=108.2

OpenStudy (darkbluechocobo):

|dw:1427479871193:dw|

OpenStudy (jhannybean):

You've got it.

OpenStudy (darkbluechocobo):

and this is where my question comes in mind. How do I get c2 ? this will be c 1

OpenStudy (jhannybean):

Now just crosscheck to see if \(108.2^\circ + 30^\circ + 41.8^\circ = 180^\circ\)

OpenStudy (darkbluechocobo):

It does

OpenStudy (jhannybean):

|dw:1427480018582:dw|

OpenStudy (jhannybean):

labeling your diagram would help tremendously.

OpenStudy (jhannybean):

\[\frac{\sin(A)}{a}= \frac{\sin(C)}{c}\]

OpenStudy (darkbluechocobo):

Question isn't it the other way around?

OpenStudy (darkbluechocobo):

or does it not matter?

OpenStudy (jhannybean):

It doesn't matter, really.

OpenStudy (jhannybean):

Ratios are ratios as long as the angle and side length are in proportion, respectfully.

OpenStudy (darkbluechocobo):

\[\frac{ 1.5 }{ \sin30 }=\frac{ c }{ \sin108.2 }\]

OpenStudy (jhannybean):

ok, and solving for c?

OpenStudy (darkbluechocobo):

\[\frac{ 1.5\sin108.2 }{ \sin30 }\]

OpenStudy (jhannybean):

mmhmm.

OpenStudy (darkbluechocobo):

I got c=2.8

OpenStudy (jhannybean):

Me too

OpenStudy (darkbluechocobo):

But since we are looking for C1 and C2 C1=108.2 how do we find C2?

OpenStudy (jhannybean):

Is C2 supposed to be the side measurement? It certainly wouldnt be the angle measurement

OpenStudy (darkbluechocobo):

It is supposed to be angles based on the answers given to choose from. They are in degrees

OpenStudy (darkbluechocobo):

s:

OpenStudy (darkbluechocobo):

C1=108.2°,C2= 48.2° C1= 48.2°,C2= 41.8° C1=108.2°,C2= 11.8° C1=41.8°,C2= 138.2° these are my options

OpenStudy (darkbluechocobo):

so its either a or c

OpenStudy (darkbluechocobo):

@freckles Could you assist?

OpenStudy (freckles):

Ok I'm going to copy what you have from above so I don't have to keep scrolling up "The information in the following problem allows you to construct 2 triangles, find C1 and C2 . A = 30°, a = 1.5 m, b = 2 m "

OpenStudy (freckles):

|dw:1427483970044:dw| this is SSA

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