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Mathematics 13 Online
OpenStudy (anonymous):

(WILL GIVE MEDAL AND FAN) Simplify. (Posting equation below.)

OpenStudy (anonymous):

\[\sin x \tan x + \cos x\]

OpenStudy (agl202):

first, simplify sinxtanx. sinx tanx = sinx * sinx / cosx = sin^2x / cosx then, add cosx and sin^2x / cosx. how? by making cosx a fraction: cosx = cos^2x / cosx (cos^2x + sin^2x) / cosx = 1 / cosx

OpenStudy (anonymous):

Thank you! Three more to go. Did you want me to post those as a new question as well?

OpenStudy (agl202):

Sure! Thx... :)

OpenStudy (anonymous):

No problem!

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