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Mathematics 21 Online
OpenStudy (anonymous):

How would you find the apothem of a regular polygon when given the length of a side, or vise versa. I've been running into problems where I have to solve this out, and I'm a bit confused. Any help would be appreciated.

OpenStudy (rational):

familiar with SOH-CAH-TOA ?

OpenStudy (anonymous):

I kind of understand them. Sine-opposite/hypotenuse, cosine=adjacent/hypotenuse, tan=Opposite/adjacent. But I don't exactly understand how to use them.

OpenStudy (rational):

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OpenStudy (rational):

can you find that angle intercepted by the side ?

OpenStudy (anonymous):

I think. So would it be 5/6(tan-1)? If so then it would be 39.805...

OpenStudy (rational):

the angle doesn't depend on the length of side

OpenStudy (rational):

Notice that it has 8 sides, so the angle is simply \(\large \dfrac{360}{8} = 45\)

OpenStudy (anonymous):

Alright, so the angle depends on the sides. So what would I need to find next?

OpenStudy (rational):

Angle|dw:1427539586920:dw|

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