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Mathematics 16 Online
OpenStudy (anonymous):

Two machines, C1 and C2, are making pins which must have a diameter of 8 cm ± .01 cm or they are rejected. Dotplots of 50 pins from each machine are displayed below. They are both on the same scale. By simply looking at the dotplots, i.e. without doing any calculations or counting, compare the distributions of the two machines:

OpenStudy (anonymous):

OpenStudy (anonymous):

@cwrw238 @saifoo.khan

OpenStudy (anonymous):

@ash2326 @pooja195 @paki

OpenStudy (kropot72):

Which machine obviously has more pins outside the specified tolerance on the diameter?

OpenStudy (anonymous):

C1 @kropot72

OpenStudy (kropot72):

Correct. Also which machine has a distribution of the diameters which approximates a normal distribution?

OpenStudy (anonymous):

C2? @kropot72

OpenStudy (kropot72):

Correct again! You can use these observations as the basis for your answer.

OpenStudy (anonymous):

okay so would that be it for this part? (there is an additional part that i would love for you to help in as well, if thats alright of course) @kropot72

OpenStudy (anonymous):

@Data_LG2

OpenStudy (anonymous):

@ash2326

OpenStudy (anonymous):

@perl

OpenStudy (anonymous):

theres another part to the question.. could you help[ me with it? @perl

OpenStudy (anonymous):

In what sense is machine C2 better at producing pins? Justify your argument. @perl

OpenStudy (perl):

C2 has less variance. this is good because suppose you have two machines both with mean 80 cm. the machine with more variance will produce more pins that are bigger than the mean or smaller than the mean. but the machine with less variance will produce pins closer to the mean. So less variance = more precision.

OpenStudy (anonymous):

thank you so much!! @perl

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