Question

8. One more rectangular-shaped piece of metal siding needs to be cut to cover the exterior of a pole barn. The area of the piece is 30 ft ^2. The length is 1 less than 3 times the width. How wide should the metal piece be? Round to the nearest hundredth.

A. 3.33 ft
B. 4.3 ft
C.1ft
D.30 ft

Answer 1

@rishavraj

Answer 2

@rational

Answer 3

@ananthus123

Answer 4

@texaschic101

Answer 5

Area of a rectangle : A = L * W
A = 30
L = 3W - 1 (length is 1 less then 3 times width)
now we sub
30 = (3W - 1)(W)
30 = 3W^2 - W
3w^2 - W - 30 = 0

quadratic formula : x = (-b (+-) sq rt b^2 - 4(a)(c)) / (2a)
a = 3, b = -1, c = -30

x = -(-1) (+-) sq rt -1^2 - 4(3)(-30) / (2(3)
x = 1 (+-) sq rt 1 + 360) / 6
x = 1 (+-) sq rt 361/6
x = 1 (+-) 19/6
x = (1 + 19)/6 = 20/6 = 3 1/3 = 3.333 <== your answer
x = (1 - 19) / 6 = -18/6 = -3 <== extraneous solution

Answer 6

Thx @texaschic101

Answer 7

not a problem...happy to help :)