Question

can someone help

Answer 1

@mathmath333

Answer 2

Apply pythagorus theorem again
this time

\(\large \color{black}{\begin{align} hypo=17,leg_1=10,leg_2=x\hspace{.33em}\\~\\
\end{align}}\)

Answer 3

17*17=289 +10*10=389

Answer 4

Use the pythagorean theorem.

a^2+b^2=c^2

c=17

b=10

Answer 5

oh so its not 17^2

Answer 6

read the question u have to find value of \(x\)

Answer 7

19.72?

Answer 8

rounded its 19.7

Answer 9

square root of 389 is 19.72

Answer 10

\(\large \color{black}{\begin{align} hypo^2=(leg_1)^2+(leg_2)^2\hspace{.33em}\\~\\
(leg_2)^2=hypo^2-(leg_1)^2\hspace{.33em}\\~\\
(leg_2)^2=17^2-10^2\hspace{.33em}\\~\\

\end{align}}\)

solve from here

Answer 11

\(\large \color{black}{\begin{align}
(x)^2=17^2-10^2\hspace{.33em}\\~\\
\end{align}}\)

Answer 12

im confused and stuck 17*17 is289 -100 would be 189

Answer 13

\(\large \color{black}{\begin{align}
(x)^2=289-100\hspace{.33em}\\~\\
(x)^2=189\hspace{.33em}\\~\\
(x)=\sqrt{189}\hspace{.33em}\\~\\
\end{align}}\)
find square root of \(189\)

Answer 14

13.74

Answer 15

yes correct

Answer 16

so rounded would be 13.7

Answer 17

yep

Answer 18

thank u forv having patience i just need someone that can walk me through it when i get stuck

Answer 19

im really trying

Answer 20

i have more if u want to help i will tag u