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How many triangles can be formed given that A=47 degrees, C=32 degrees, c=12?
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@freckles
I'm getting h<a<b, two triangles..?
<A=47 <B=101 <C=32 a=16.56 b=22.23 c=12
Solved for the first triangle, is there one more?
The only ambiguous case is the SSA. You have two angles and a side. |dw:1427665478813:dw| you don't two check for a second triangle.
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