Help!

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

y = four thirdsx + 8
y = four thirdsx + 3
y = -three fourthsx + 8
y = -three fourthsx + 3

Question

Help!

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

 y = four thirdsx + 8
 y = four thirdsx + 3
 y = -three fourthsx + 8
 y = -three fourthsx + 3

perl · Answer

hint: For the given equation , first solve for y

anonymous · Answer

how do i solve for y? sorry i dont know how to do this...

anonymous · Answer

@perl

perl · Answer

$$
\Large 
{4x - 3y = -12\\
\ \iff  	ext{subtract 4x from both sides}\~\ 
-3y = -4x - 12
\\ \iff  	ext{divide both sides by -3}\~\ 
y = \frac{-4}{3}x - \frac{12}{3}

}
$$

anonymous · Answer

y=1.3x - 4?

anonymous · Answer

im not sure what the next step is after what you posted

anonymous · Answer

@perl

anonymous · Answer

i need to go to sleep, its 2:10 AM and i have to wake up at 5:20 for school :( can some one please help me?

butterflydreamer · Answer

perl already walked you through it :) what don't you understand?

anonymous · Answer

what do i have to do after  y=-4/3x-12/3

butterflydreamer · Answer

actually firstly i think... there may be an error in that equation :) let's start over.

anonymous · Answer

alright :)

butterflydreamer · Answer

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