Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

Will somebody please help me, been stuck on this same question for an hour now. :/

OpenStudy (epoweritheta):

tell me

OpenStudy (anonymous):

Tom has $10 that he wants to use to buy pens and pencils. However, he does not want to buy more pens than pencils. A pen costs $3, and a pencil costs $1. Which graph represents this scenario? (Here, x represents the number of pens and y the number of pencils.)

OpenStudy (epoweritheta):

ninja , if he buys x pens and y pencils , using 10 dollars , i say , 10 =3x+y okay ??

OpenStudy (anonymous):

Yes. I am stuck on what happens after that. How do i graph it.

OpenStudy (epoweritheta):

now note he does not want x>y ie more pens than pencils okay ??? ie he wants x<=y

OpenStudy (anonymous):

Yes

OpenStudy (epoweritheta):

see see , he may or maynot use his total 10 dollars so , 3x+y <=10

OpenStudy (anonymous):

OKay, This making sense now, what to do next?

OpenStudy (anonymous):

OpenStudy (anonymous):

Is the first graph the answer, sir?

OpenStudy (epoweritheta):

dont call me sir , i am ur friend , wait i wil check

OpenStudy (anonymous):

Haha. Ok, friend

OpenStudy (epoweritheta):

can u plot 3x+y <=10 for me in a paper ??

OpenStudy (anonymous):

Sorry, i cannot, i m in library. Not having any paper. But i think the answer would be c now, not a

OpenStudy (epoweritheta):

see what would be the slope of the line -3 right ??

OpenStudy (anonymous):

OKay, thank you i have my answer.

OpenStudy (epoweritheta):

hey i am sorry since all the lines are the same u dont have to draw the graph , just substitute a point from the region and see whether it is satisfying our initial condition

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!