Question

Identify the vertex, focus, directrix, and min/max value of each.
y+1=−(x−1)2

Answer 1

HI!!

Answer 2

you got the vertex? that is the easiest part

Answer 3

yea i got 1,-1

Answer 4

ok that is good

Answer 5

you know this opens down right?

Answer 6

down

Answer 7

it looks like \(4p(y-k)=(x-h)^2\) so the vertex is \((1,-1\) like you said, and \(4p=-1\) so \(p=-\frac{1}{4}\) the focus is \(\frac{1}{4}\) units DOWN from \((1,-1)\) namely at \((1,-\frac{5}{4})\) and the directrix is \(\frac{1}{4}\) units up from the vertex, i.e at \(y=-\frac{3}{4}\)

Answer 8

How do i get the max or min? would it be the max -2 and min 2?