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Mathematics 21 Online
OpenStudy (howard-wolowitz):

ONE QUESTION!

OpenStudy (howard-wolowitz):

OpenStudy (howard-wolowitz):

@mathmate

OpenStudy (133):

A and I feel like I'm learning from your work

OpenStudy (howard-wolowitz):

@Austin6i6

OpenStudy (howard-wolowitz):

yeah I think its A as-well

OpenStudy (133):

Is it right??

OpenStudy (howard-wolowitz):

i dont wanna submit it yet till someone else says something

OpenStudy (amorfide):

C I will explain why

OpenStudy (howard-wolowitz):

how C

OpenStudy (amorfide):

think of |x|=x |-x|=x as a reflection in the x axis

OpenStudy (amorfide):

oops let me re write that

OpenStudy (amorfide):

|x|= x |-x|=x now we want to find the equation of the line we know that the y intercept of the line with a negative gradient, it crosses 4 since we know from |-x|=x when x=0 y=4 because it was reflected in the x axist therefore before reflection y=-4 so we know the y intercept of the line with a positive gradient is -4 since an equation of a line is in the form y=mx+c C is the y intercept, so we know that C=-4 therefore the y intercept is -4 so we have an equation of y=mx -4 now we need the gradient but since all the possible given answers all have a gradient of 1 we know we have the equation y=x-4 now we want to draw the graph for the absolute value of x-4 so we have |x-4|

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