ONE QUESTION!
@mathmate
A and I feel like I'm learning from your work
@Austin6i6
yeah I think its A as-well
Is it right??
i dont wanna submit it yet till someone else says something
C I will explain why
how C
think of |x|=x |-x|=x as a reflection in the x axis
oops let me re write that
|x|= x |-x|=x now we want to find the equation of the line we know that the y intercept of the line with a negative gradient, it crosses 4 since we know from |-x|=x when x=0 y=4 because it was reflected in the x axist therefore before reflection y=-4 so we know the y intercept of the line with a positive gradient is -4 since an equation of a line is in the form y=mx+c C is the y intercept, so we know that C=-4 therefore the y intercept is -4 so we have an equation of y=mx -4 now we need the gradient but since all the possible given answers all have a gradient of 1 we know we have the equation y=x-4 now we want to draw the graph for the absolute value of x-4 so we have |x-4|
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