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what is the domain? f(x)=3(x-2) just pretend the (stuff in here) is under the square root
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you cant have a negative under a root for starters
that would be complex and imaginary.
it's not a negative, it's just x-2
yes i know but since it is domain we are looking at along the x axis knowing that we cant have a negative will help us look at the domain. so what is the lowest number we can put in for x that will keep it positive under the root
3?
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lets try it.
|dw:1427848296054:dw| yup that works but we can still go lower
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