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Mathematics 13 Online
OpenStudy (anonymous):

what is the domain? f(x)=3(x-2) just pretend the (stuff in here) is under the square root

OpenStudy (anonymous):

you cant have a negative under a root for starters

OpenStudy (anonymous):

that would be complex and imaginary.

OpenStudy (anonymous):

it's not a negative, it's just x-2

OpenStudy (anonymous):

yes i know but since it is domain we are looking at along the x axis knowing that we cant have a negative will help us look at the domain. so what is the lowest number we can put in for x that will keep it positive under the root

OpenStudy (anonymous):

3?

OpenStudy (anonymous):

lets try it.

OpenStudy (anonymous):

|dw:1427848296054:dw| yup that works but we can still go lower

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