help with inverse functions!!
solve for x in terms of f(x)
sqrt(y-5) + 1 and y-5 >= 0 when y >= 5 so you did fine
ah great, thank you! these questions confuse me, so i am never sure if i get the correct answer after ive solved. can i post the others on this question? im taking the practice test but they dont tell me the correct answers when i get them wrong.
we can work a few, prolly not all tho
explain the answer you want to choose, just so i can see if your thought process is sane enough
haha okay sounds good, thank you! i will post the ones i come across that im unsure of.
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i cant recall how to solve these..i know there are only a few steps though im just stuck
if X is the domain of f, and Y is the range of f then Y is the domain of inverse, and X is range of inverse
all in inverse does, is take the values of a range and gives back the value that got you there.
hmm okay. would that leave the answer to be A? im still not quite sure
what is the domain of f?
is it f^-1?
you are given f, what is the domain of f? what values of x can you use in the defined function?
okay so you are given x-9/21-4x
y = (x-9)/(21-4x) y(21-4x) = x-9 21y -4yx = x-9 21y + 9 = x +4yx 21y + 9 = x(1 +4y) (21y + 9)/(1 +4y) = x y cannot be -1/4, since it zeroes out the bottom so B fits the bill right?
okay so you solve for x? yes that would make B the answer
i think B has an error tho, in the print
other than that, its the best for the buck
okay thanks! so to solve it you move it around so that x is all alone. but how is it that you determine the domain from that?
domain is all usable values
1 + 4y is in the denominator, we cant devide by 0 so 1 + 4y = 0 when y=-1/4
is there a value of x that makes f equal to -1/4? -1/4 = (x-9)/(21-4x) -1(21-4x) = 4(x-9) 4x-21 = 4x-9 so when does 21 = 9? never
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