Which equation represents y=-x^2+4x-1 in vertex form?
a. y=-(x-2)^2+3
b. y=-(x+2)^2-3
c. y=-(x+2)^2-1
d. y=-(x-2)^2+5
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OpenStudy (anonymous):
Do you know what vertex form is?
OpenStudy (omgthatgirl):
no.. :/
OpenStudy (anonymous):
Okay, do you know how to solve for the vertex?
OpenStudy (omgthatgirl):
no..sorry
OpenStudy (anonymous):
Do you want to learn any of it or do you just want the answer...?
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OpenStudy (omgthatgirl):
both please
OpenStudy (anonymous):
Solving for the vertex is simple
the equation is -x^2+4x-1. You should have learned that this means: a=(-1), b=4 and c=(-1). To solve, you just need to know two formulas: h=\[-b/(2a)\] and k=\[c-b^2/(4a)\]
OpenStudy (anonymous):
Make sense so far?
OpenStudy (omgthatgirl):
yes
OpenStudy (anonymous):
okay, so you plug in the numbers. \[h= -(4)/2(-1)\] that is 2, h=2.
Now you use the formula and find what k equals.
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OpenStudy (omgthatgirl):
3?
OpenStudy (omgthatgirl):
@Bmannn13
OpenStudy (anonymous):
Sorry, I caught a really bad lag; you still there?
OpenStudy (omgthatgirl):
its fine
OpenStudy (anonymous):
Yes, it's 3.
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OpenStudy (omgthatgirl):
ok
OpenStudy (anonymous):
All the algebra is done, so now we are at the easy part. Plug it in. Vertex form is y=a(x-h)^2+k. knowing that, plug all the numbers in and you've got the answer.
OpenStudy (omgthatgirl):
ok and what is x?
OpenStudy (omgthatgirl):
is this right
k=3
h=2
a=-1
OpenStudy (anonymous):
x is a variable, so you just leave it as x; yes, exactly.
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