Question

Solve the equation 36x^2+25=0

a. +6/5i
b. +5/6i
c. +25/36i
d. +36/25i

Answer 1

I could always help again.

Answer 2

\(\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad
a^2-b^2 = (a-b)(a+b)\qquad thus
\\ \quad \\
36x^2+25=0\quad
\begin{cases}
36\to 6^2\\
25\to 5^2
\end{cases}\qquad \implies 6^2x^2+5^2=0\implies (6x)^2+5^2=0\)

Answer 3

C

Answer 4

and ... so @Omgthatgirl