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Mathematics 8 Online
OpenStudy (anonymous):

Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordinates and descriptions of shapes used. Then, find the actual area of the figure.

OpenStudy (anonymous):

OpenStudy (studygurl14):

Hello @Imz0901 I would find the area of the two triangles, and of the square, and add them together.

OpenStudy (studygurl14):

@lmz0901 And welcome to openstudy!

OpenStudy (anonymous):

Hi, thank you for helping me out! @StudyGurl14

OpenStudy (anonymous):

what would i do to find the area?

OpenStudy (studygurl14):

You're welcome. :) Well, find the legnth of one side of the square, and find the height and base of the triangles.

OpenStudy (studygurl14):

OpenStudy (anonymous):

@StudyGurl14 would the area for the blue triangle be 15???

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (anonymous):

@GretaKnows

OpenStudy (anonymous):

will give medals

OpenStudy (anonymous):

yes. the area of the blue triangle will be 15.

OpenStudy (anonymous):

@GretaKnows thank you!! and for the square 6 ?

TheSmartOne (thesmartone):

Yes, the area of the blue triangle is 15. :)

OpenStudy (anonymous):

http://prntscr.com/6oe5xr

TheSmartOne (thesmartone):

And for the square, area of a square is \(\sf side^2\) And the length of the side is 6. So plug that into the formula

OpenStudy (anonymous):

oops its (1*6)/2=

OpenStudy (anonymous):

@TheSmartOne 36?

OpenStudy (anonymous):

@GretaKnows picture helped a lot, thanks!!

TheSmartOne (thesmartone):

Correct :)

OpenStudy (anonymous):

yes so the square is 36 now solve the green triangle.

OpenStudy (anonymous):

@TheSmartOne yay, thanks a lot!

OpenStudy (anonymous):

@GretaKnows green triangle is 6 so .. (1/2)bh = (1/2)*6 = 3?

TheSmartOne (thesmartone):

Np :)

OpenStudy (anonymous):

yes http://prntscr.com/6oe7r1 now add together all of the areas

OpenStudy (anonymous):

@GretaKnows I got 54

OpenStudy (anonymous):

yep. 54 is the area of the figure! good job :)

OpenStudy (anonymous):

@GretaKnows thanks soooo much :D

OpenStudy (anonymous):

no problem :) do you need help on the other part of the question?

OpenStudy (anonymous):

@GretaKnows No, I got it from here (:

OpenStudy (anonymous):

okay! tag me if you need help! have good rest of your day :)

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