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OpenStudy (anonymous):
*Yawn*
Miracrown (miracrown):
lol
Miracrown (miracrown):
That kid has prolly fallen asleep
OpenStudy (anonymous):
Just look at your forces on the x - axis, and you'll get your answer
Miracrown (miracrown):
up and down forces are equal, there is no buoyant force so therefore lets eliminate option a out of the way
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Miracrown (miracrown):
If the velocity were constant (meaning no unbalanced force), then it would be inertial.
But that is not the case here. In horizontal direction, there is 6000 N to the left, and 5000 N to the right. hence there is a net force. They are not balanced. Hence it is NOT inertia so we can rule out option c too
From what I already said, you can tell us the answer now - Is it balanced or unbalanced?
OpenStudy (anonymous):
balanced?
Miracrown (miracrown):
LOL no barb think 1 more time and you'll be right
OpenStudy (anonymous):
|dw:1427967691800:dw| is that balanced?
Miracrown (miracrown):
the ans shud be pwtty obvious now
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OpenStudy (anonymous):
unbalanced
Miracrown (miracrown):
YES YOU GOT IT CONGRATS YOU'RE SO SMART!!! :D
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
OpenStudy (anonymous):
Good job buddy!
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OpenStudy (anonymous):
I see OS only loads if you click on notification
Miracrown (miracrown):
Yea, same here been like that for a while now
OpenStudy (anonymous):
@Miracrown
OpenStudy (anonymous):
What's the net force
OpenStudy (anonymous):
Think about this for a bit, what's going to happen vertically? Horizontally?
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OpenStudy (anonymous):
vertcly
OpenStudy (anonymous):
?
OpenStudy (anonymous):
toward th right?
Miracrown (miracrown):
YOU GOT IT YAY
OpenStudy (anonymous):
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OpenStudy (anonymous):
Yeah, but next time try to understand what's going on in the picture, don't just pick the one with the biggest number. Notice the vertical forces cancel out, and you have a net force towards the right.
Miracrown (miracrown):
What he said ^
Miracrown (miracrown):
For your next q, which one do you pick and why?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
What is speed?
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OpenStudy (anonymous):
(Think units)
OpenStudy (anonymous):
3.0m/s
Miracrown (miracrown):
Formula: Average speed = total distance/ total time
Miracrown (miracrown):
\(\color{blue}{\text{Originally Posted by}}\) @barbdewysveck1
3.0m/s
\(\color{blue}{\text{End of Quote}}\)
YOU GOT IT ONCE AGAIN
Miracrown (miracrown):
Do you have anymore questions? I am falling asleep; my one eye is fully closed, the other one is half way there ... hurry up pls before I die completely
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OpenStudy (anonymous):
Miracrown (miracrown):
This better not be a test, I trust you.
OpenStudy (anonymous):
its not
Miracrown (miracrown):
What do you think and why
Miracrown (miracrown):
Try to do a sketch, that will help you find the answer
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