Ask your own question, for FREE!
Earth Sciences 25 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

@Miracrown

OpenStudy (anonymous):

@kittiwitti1 @domebotnos @danish071996 @jeweaver6895 @Bananas1234 @c0decracker

OpenStudy (anonymous):

@iambatman @SyedMohammed98

OpenStudy (anonymous):

Make a guess

OpenStudy (anonymous):

Let me ask you, is that car at equilibrium?

OpenStudy (anonymous):

*Yawn*

Miracrown (miracrown):

lol

Miracrown (miracrown):

That kid has prolly fallen asleep

OpenStudy (anonymous):

Just look at your forces on the x - axis, and you'll get your answer

Miracrown (miracrown):

up and down forces are equal, there is no buoyant force so therefore lets eliminate option a out of the way

Miracrown (miracrown):

If the velocity were constant (meaning no unbalanced force), then it would be inertial. But that is not the case here. In horizontal direction, there is 6000 N to the left, and 5000 N to the right. hence there is a net force. They are not balanced. Hence it is NOT inertia so we can rule out option c too From what I already said, you can tell us the answer now - Is it balanced or unbalanced?

OpenStudy (anonymous):

balanced?

Miracrown (miracrown):

LOL no barb think 1 more time and you'll be right

OpenStudy (anonymous):

|dw:1427967691800:dw| is that balanced?

Miracrown (miracrown):

the ans shud be pwtty obvious now

OpenStudy (anonymous):

unbalanced

Miracrown (miracrown):

YES YOU GOT IT CONGRATS YOU'RE SO SMART!!! :D

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

OpenStudy (anonymous):

Good job buddy!

OpenStudy (anonymous):

I see OS only loads if you click on notification

Miracrown (miracrown):

Yea, same here been like that for a while now

OpenStudy (anonymous):

@Miracrown

OpenStudy (anonymous):

What's the net force

OpenStudy (anonymous):

Think about this for a bit, what's going to happen vertically? Horizontally?

OpenStudy (anonymous):

vertcly

OpenStudy (anonymous):

?

OpenStudy (anonymous):

toward th right?

Miracrown (miracrown):

YOU GOT IT YAY

OpenStudy (anonymous):

OpenStudy (anonymous):

Yeah, but next time try to understand what's going on in the picture, don't just pick the one with the biggest number. Notice the vertical forces cancel out, and you have a net force towards the right.

Miracrown (miracrown):

What he said ^

Miracrown (miracrown):

For your next q, which one do you pick and why?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

What is speed?

OpenStudy (anonymous):

(Think units)

OpenStudy (anonymous):

3.0m/s

Miracrown (miracrown):

Formula: Average speed = total distance/ total time

Miracrown (miracrown):

\(\color{blue}{\text{Originally Posted by}}\) @barbdewysveck1 3.0m/s \(\color{blue}{\text{End of Quote}}\) YOU GOT IT ONCE AGAIN

Miracrown (miracrown):

Do you have anymore questions? I am falling asleep; my one eye is fully closed, the other one is half way there ... hurry up pls before I die completely

OpenStudy (anonymous):

Miracrown (miracrown):

This better not be a test, I trust you.

OpenStudy (anonymous):

its not

Miracrown (miracrown):

What do you think and why

Miracrown (miracrown):

Try to do a sketch, that will help you find the answer

Miracrown (miracrown):

|dw:1427969858026:dw| Please proceed

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!