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how do you get the answer 5π/6 by solving tan^-1(1/-√3) + 1π ? all the steps or any links that I can study them would be really great :) Thanks
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tan^-1(1/-√3) first find the angle less than 90 dgrees ( in first quadran) that has a tan of 1/sqrt3 there's a standard triangle which can be used |dw:1427987904232:dw|
thats anggle x which is 30 degrees or pi/6 radians
but we have negative 1 / sqrt3 which will givw an angle in the second quadrant
|dw:1427988123531:dw|
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