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Mathematics 14 Online
OpenStudy (fredfredburgeryes):

Help! -le flail- Will Medal

OpenStudy (fredfredburgeryes):

this is the table

OpenStudy (fredfredburgeryes):

Part A: What would most likely be the number of sweaters sold if the temperature is 27 degrees Celsius? Part B: Predict a possible correlation coefficient for the data in the table and explain why you think your prediction is a good value for the data. Part C: George says that if a discount is given on the sweaters, the sale of sweaters would increase. Is this an example of correlation or causation? Justify your answer.

OpenStudy (anonymous):

Do you know how to solve it?

OpenStudy (fredfredburgeryes):

To be honest I probably would understand it if I didn't have a splitting headache from the construction going on outside.... I would really appreciate the help

OpenStudy (anonymous):

what is the pattern? number of sweaters sold is decreasing by the same value

OpenStudy (fredfredburgeryes):

decreasing by 8 per every -2 degrees c?

OpenStudy (anonymous):

yeah so now we can say that for every one degree the value is decreasing by 4

OpenStudy (fredfredburgeryes):

so A would be 142

OpenStudy (anonymous):

yes

OpenStudy (fredfredburgeryes):

okay! cool, on to part B!

OpenStudy (anonymous):

ok so lets make a function out of the data since its linear we can use y=mx + b

OpenStudy (anonymous):

what is the slope m rise/run

OpenStudy (fredfredburgeryes):

4?

OpenStudy (anonymous):

yes because for every one x there is 4 up

OpenStudy (fredfredburgeryes):

but the table has intervals of 2 degrees, so wouldn't it be 8?

OpenStudy (anonymous):

you could say 8/2 8 y for every 2 x but 8/2 = 4

OpenStudy (fredfredburgeryes):

so is that the slope or the answer or what. sorry man theyre digging up some sort of water line and my ears are practically ringing T.T

OpenStudy (anonymous):

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