Question

How do i simplify problems like these?

Answer 1

\(\bf \cfrac{x^8y^{-26}}{x^{14}y^{-5}\times x^{-39}y^{-21}}\implies
\cfrac{x^8y^{-26}}{x^{14}y^{-5} x^{-39}y^{-21}}
\\ \quad \\
a^{-{\color{red} n}} \implies \cfrac{1}{a^{\color{red} n}}\qquad \qquad

\cfrac{1}{a^{\color{red} n}}\implies a^{-{\color{red} n}}
\\ \quad \\
% negative exponential denominator
a^{{\color{red} n}} \implies \cfrac{1}{a^{-\color{red} n}}
\qquad \qquad

\cfrac{1}{a^{-\color{red} n}}\implies \cfrac{1}{\frac{1}{a^{\color{red} n}}}\implies a^{{\color{red} n}} \qquad thus

\\ \quad \\
\cfrac{x^8}{1}\cdot \cfrac{y^{-26}}{1}\cdot
\cfrac{1}{x^{14}}\cdot \cfrac{1}{y^{-5}}\cdot \cfrac{1}{x^{-39}}\cdot \cfrac{1}{y^{-21}}
\\ \quad \\
x^8y^{-26}x^{-14}y^{+5} x^{+39}y^{+21}\implies x^8x^{-14}x^{+39}y^{-26}y^{+5} y^{+21}

\\ \quad \\
\implies ?\)

Answer 2

is it 33 and 0? @jdoe0001