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Mathematics 8 Online
OpenStudy (nathanjhw):

Using the Trapezoid Rule with n = 8 to approximate the arc length of the graph of y=2x^3-2x+1 from A (0,1) to B(2,13) you get (to three decimal places):

OpenStudy (nathanjhw):

6.900 13.896 14.093 13.688 13.697

OpenStudy (nathanjhw):

@perl

OpenStudy (nathanjhw):

@Zale101

OpenStudy (nathanjhw):

@Zale101

OpenStudy (amistre64):

well, arc length is just pythagorean in this case, sqrt(dx^2+dy^2)

OpenStudy (amistre64):

|dw:1428011344056:dw| ds is approximately the length of the curve

OpenStudy (amistre64):

divide the x interval into 8 equal parts, and that is equal to dx dy is determined part for part and is more computationally .... longer

OpenStudy (nathanjhw):

So how do we find dx and dy? Do we use (0,1) and (2,13)?

OpenStudy (nathanjhw):

@amistre64

OpenStudy (nathanjhw):

@phi

OpenStudy (nathanjhw):

@Loser66

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