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Using the Trapezoid Rule with n = 8 to approximate the arc length of the graph of y=2x^3-2x+1 from A (0,1) to B(2,13) you get (to three decimal places):
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6.900 13.896 14.093 13.688 13.697
@perl
@Zale101
@Zale101
well, arc length is just pythagorean in this case, sqrt(dx^2+dy^2)
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|dw:1428011344056:dw| ds is approximately the length of the curve
divide the x interval into 8 equal parts, and that is equal to dx dy is determined part for part and is more computationally .... longer
So how do we find dx and dy? Do we use (0,1) and (2,13)?
@amistre64
@phi
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@Loser66
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