What is the net distance traveled by the ant over the time interval 0 ≤ t ≤ 8?
So I find the area under the first semicrcle, the big triangle, and the small triangle?
what is that graph of, velocity or displacement?
velocity
ok then we can use geometry and calculate the areas bounded by the curve and the x axis
the first shape is a semicircle. we know from geometry the area of a circle
then take half of that area
A= 1/2 pi r^2 = 1/2 pi 1^2 = pi/2
correct
The area of the big triangle is 1/2 bh = 1/2 (4) (3) = 1/2 (12) = 6
The area of the small triangle is 1/2 bh = 1/2 (2) (1) = 1/2 (2) = 1
Therefore I have 6+1 +pi/2 = 7 +pi/2 right?
Actually I minus the 1 and get 6-1 +pi/2 = 5 +pi/2 right?
@perl
well the question says 'net distance'
So I minus the 1 because it is negative.
Under the x-axis.
correct, we will subtract (i think)
Well adding it means it would not equal any of my answers, so I'll assume we subtract. Also, the second part of the question asks for the total distance and there I would add the 1 to get 7 +pi/2.
According to this website net distance is the same as displacment http://mrkhadem.com/net_and_total_distance_traveled.htm
right
Alright thank you very much! You really helped me out and made it easy.
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