Zen rolled a fair six-sided die 12 times. The table below shows the number of times each number was rolled:
Number Cube ExperimentNumber on
the Cube Number of
Times
Appeared
1 0
2 3
3 1
4 2
5 2
6 4
According to the results in the chart, what is the experimental probability of getting a number greater than 3 on the die?
3 over 12 6 over 12 9 over 12 8 over 12
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (anonymous):
@jim_thompson5910 you there?????
jimthompson5910 (jim_thompson5910):
no offense, but you have to be patient
jimthompson5910 (jim_thompson5910):
how many times does a '4' show up (based on the table)?
OpenStudy (anonymous):
only once
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jimthompson5910 (jim_thompson5910):
no, look at the table again
OpenStudy (anonymous):
no twice
jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
so four plus 4 is eight
jimthompson5910 (jim_thompson5910):
how many times does 5 show up
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OpenStudy (anonymous):
once
jimthompson5910 (jim_thompson5910):
you sure?
OpenStudy (anonymous):
yeah it only show once
jimthompson5910 (jim_thompson5910):
look in column 2 next to the '5'
jimthompson5910 (jim_thompson5910):
column 2 records how many times a certain face shows up
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OpenStudy (perl):
*
OpenStudy (anonymous):
2 times
jimthompson5910 (jim_thompson5910):
better
jimthompson5910 (jim_thompson5910):
how about 6? how many times does 6 show up?
OpenStudy (anonymous):
one time
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OpenStudy (anonymous):
so it would be 6/12
jimthompson5910 (jim_thompson5910):
one time? are you sure?
OpenStudy (anonymous):
yes one time
jimthompson5910 (jim_thompson5910):
again look to the right of 6
OpenStudy (anonymous):
4 times
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jimthompson5910 (jim_thompson5910):
yes
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
ok add up the values 2, 2, 4 (that are next to 4,5,6)
so we get: 2+2+4 = 8
this is out of 12 since the numbers in column 2 add to 12
so that's why the answer is 8/12
OpenStudy (anonymous):
oh ok now i understand (:
OpenStudy (anonymous):
how do i medal you.
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