Question

find the height in feet of the rock after 10 seconds in the air

Answer 1

Is there more information?

Answer 2

yes it the whole problem do you want me to write it out

Answer 3

sure :p

Answer 4

that is it

Answer 5

that website says, "AccessDeniedAccess"

Answer 6

cant see that its restricted

Answer 7

what i think you are trying to do is have a rock fall to the ground?

Answer 8

that website says, "AccessDeniedAccess"

Answer 9

d = Velocity(time) + (1/2)(9.8)time^2

Answer 10

a rock is launched from a cannon
height ,h(x), can be represented by a quadratic function in terms of x in seconds

after 1 second the rock is 58 feet in the
air after 2 seconds it is 112 feet in the air

Answer 11

is this a math class or a physics?

Answer 12

math

Answer 13

so we need to make a quadratic equation such as y = x^2 that fits that data

Answer 14

ok so what i do next

Answer 15

https://www.youtube.com/watch?v=DHYPjhQNHIo

Answer 16

we have two points so we can use this formula

Answer 17

ok

Answer 18

points = (1,58)
(2,112)

Answer 19

so how do i do this

Answer 20

sorry i suck at math and i really need to pass this test

Answer 21

y = vi.t + 0.5.g.t^2
58 = vi + 0.5*32
vi = 42 ft/s

y10 = 42*10 + 0.5*32*10^2 = 2000'

Answer 22

is that the answer

Answer 23

seems like we need more information. otherwise we would just have to use physics formulas

Answer 24

ok cool

Answer 25

that is what i used to get the answer

Answer 26

ok

Answer 27

so yeah 2000' is the answer

Answer 28

it said it was wrong