A box has 1 red marble, 3 blue marbles, and 4 green marbles. Maya draws a blue marble randomly from the box, replaces it, and then draws another marble randomly. What is the probability of drawing 2 blue marbles in a row? Explain your answer.
@Michele_Laino u think u culd help me some more ^.^?
at the first draw, the probability for getting a blue marble, is: 3/8 then Maya replaces it into the box
at the second draw the probability to getting a blue marble, is the same, namely 3/8
now, what is the requested probability?
so both probabilities is 3/8 ^.^ ?
yes! Since Maya replaces the extracted marble into the box every time
then the requested probability is: 3/8 * 3/8 = ...?
\[\frac{3}{8} \times \frac{3}{8} = ...?\]
its 9/64? i think
yes!
how do i simplify tht ^.^
we can not simplify that fraction, since 9 and 64 have no common divisors
oh okay thx again is it ok if i tag u in a few more questions?
ok!
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