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Mathematics 13 Online
OpenStudy (studygurl14):

please help (see attachment)

OpenStudy (studygurl14):

OpenStudy (studygurl14):

@amistre64 @jim_thompson5910 @freckles @dan815

TheSmartOne (thesmartone):

Is this a worksheet?

OpenStudy (studygurl14):

No. It's a practice online.

OpenStudy (studygurl14):

I go to an online school, so all my "worksheets" are online practices, i suppose

TheSmartOne (thesmartone):

Because I found this right now while I was googling your question http://mchenrymath2.yolasite.com/resources/Unit_7_Sequences_Series/0%20Sigma%20Notation%20and%20nth%20term%20SG%20and%20Practice%20Master.pdf

TheSmartOne (thesmartone):

On the last page, last question on the right.

Nnesha (nnesha):

|dw:1428111653742:dw| ??

OpenStudy (studygurl14):

I think my practice problems come from actual worksheets because it says Advanced Mathematical concepts in the corner of the pages, which is my textbook

TheSmartOne (thesmartone):

To solve this question: We would have to do these steps: 9c5+9c6+9c7+9c8+9c9 =?

OpenStudy (studygurl14):

What's c?

TheSmartOne (thesmartone):

Because it says "at least have 5 seniors"

Nnesha (nnesha):

at *least* 5

TheSmartOne (thesmartone):

nCr = \(\huge\frac{n!}{r!(n-r)!}\)

OpenStudy (studygurl14):

Oh, right. Okay, I'll try that

jimthompson5910 (jim_thompson5910):

c isn't a variable in this case, it's more like a function. It's the combination function to be exact Instead of saying n C r, this notation may be better \[\Large C(n,r) = \frac{n!}{r!*(n-r)!}\]

OpenStudy (studygurl14):

i don't think that it is 9c5+9c6+9c7+9c8+9c9 because 9c5 alone is 126, and the answer is 256

TheSmartOne (thesmartone):

the numbers get smaller. :)

OpenStudy (studygurl14):

oh, right....duh...

OpenStudy (studygurl14):

126+84+36+9+1=256 OMG, thanks!

TheSmartOne (thesmartone):

No problem :)

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