Question

Metallic copper is formed when aluminum reacts with copper(II) sulfate. How many grams of metallic copper can be obtained when 54.0 g of Al react with 319 g of CuSO4? Al + 3CuSO4→ Al2(SO4)3 +3Cu

Answer 1

If calculate the amount of moles that are in 54 grams of AL and 319 grams of CuSO4, you'd notice that AL=27 grams, CuSo4=162 grams

that's one half of what they want to react with. so you'd multiply the entire equation by 2.

3CU x 2=?

Answer 2

it should be 127.6 g Cu

Answer 3

CuSO4 required: 54 g Al * 1mol Al/27gr Al*3 mol CuSO4 /1 mol Al *160gr CuSO4/1 mol CuSO4 = 960 gr but we have 319 gr so CuSO4 is limiting then;
m(CU) = 319 gr CuSO4*1molCuSO4/160 CuSO4*3mol cu/3mol CuSO4*64 g Cu/1 mol Cu = 127.6 gr