HELP ASAP!!!! MEDAL + FAN!!!!
Draw a line with a slope of 1/4 through the point (0,-4).
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OpenStudy (anonymous):
OpenStudy (anonymous):
@help_people @paki @Preetha @freckles
OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
I think it is A idk
OpenStudy (anonymous):
@Figureskater12
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OpenStudy (nincompoop):
this is not about guessing
try to solve it
OpenStudy (anonymous):
ok i will try give me a sec
OpenStudy (mtalhahassan2):
is this all picture given already
OpenStudy (anonymous):
A because it passes through 0 and -4 is this correct?
OpenStudy (mathmath333):
|dw:1428169124569:dw|
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OpenStudy (michele_laino):
hint:
we have to apply this equation:
\[y - {y_1} = m\left( {x - {x_1}} \right)\]
where m is the slope and (x_1, y_1) is the point at which our line has to passes
OpenStudy (anonymous):
C?
OpenStudy (anonymous):
im still confused...
OpenStudy (mtalhahassan2):
I guess the pic are wrong
OpenStudy (mtalhahassan2):
bez the graph has to be on (0,-4)
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OpenStudy (mtalhahassan2):
|dw:1428169436211:dw|
OpenStudy (anonymous):
C has a point on 0,-4
OpenStudy (mathmath333):
the pic is correct
OpenStudy (mtalhahassan2):
like as this one
OpenStudy (anonymous):
so it is C
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OpenStudy (mtalhahassan2):
yes
OpenStudy (mtalhahassan2):
sorry my bad i don't see the pic correctly
OpenStudy (michele_laino):
hint:
after substitution, of your data into my equation, you should get this:
\[y + 4 = \frac{1}{4}x\]
OpenStudy (nincompoop):
great
OpenStudy (anonymous):
-4 + 4 = 1/4 x 0 ?
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OpenStudy (mathmath333):
it was easy as it was the only graph which passes through point \((0,-4)\)
but in case if the option had more than \(2\) lines passing through the same point u need to check the two points and find the slope if it equals \(\dfrac14\)
OpenStudy (anonymous):
How do i check if the two points equal a slope of 1/4?
OpenStudy (anonymous):
got it y2 - y1 / x2 - x1 = slope
OpenStudy (mathmath333):
in graph the the two points are
\((x_1,y_1)\implies (-4,-5)\) and \((x_2,y_2)\implies (0,-4)\)
formula for slope is \(\dfrac{y_2-y_1}{x_2-x_1}\)
OpenStudy (anonymous):
Thanks anyways :D
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