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Confidence interval problem. Photo attached!
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mean = 13.77, n=11, standard deviation = 1.15 do i have to incorporate the 0.5 standard deviation that was give?
ow my eyes!!!
a confidence interval uses a standard error adjustment, not a standard deviation adjustment so yes, we need sigma
\[CI:=~\mu_x\pm z_{k\%}\left(\frac{\sigma}{\sqrt{n}}\right)\]
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if sigma (population standard deviation) is known, then we use it instead of s (sample standard deviation)
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